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4x^2-93-(1-9x)-(3-8x)=2(2x+1)(x-1)
We move all terms to the left:
4x^2-93-(1-9x)-(3-8x)-(2(2x+1)(x-1))=0
We add all the numbers together, and all the variables
4x^2-(-9x+1)-(-8x+3)-(2(2x+1)(x-1))-93=0
We get rid of parentheses
4x^2+9x+8x-(2(2x+1)(x-1))-1-3-93=0
We multiply parentheses ..
4x^2-(2(+2x^2-2x+x-1))+9x+8x-1-3-93=0
We calculate terms in parentheses: -(2(+2x^2-2x+x-1)), so:We add all the numbers together, and all the variables
2(+2x^2-2x+x-1)
We multiply parentheses
4x^2-4x+2x-2
We add all the numbers together, and all the variables
4x^2-2x-2
Back to the equation:
-(4x^2-2x-2)
4x^2+17x-(4x^2-2x-2)-97=0
We get rid of parentheses
4x^2-4x^2+17x+2x+2-97=0
We add all the numbers together, and all the variables
19x-95=0
We move all terms containing x to the left, all other terms to the right
19x=95
x=95/19
x=5
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